X^2-272x+4096=0

Solution for X^2-272x+4096=0 equation:

X^2-272X+4096=0

a = 1; b = -272; c = +4096;
Δ = b2-4ac
Δ = -2722-4·1·4096
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{57600}=240$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-272)-240}{2*1}=\frac{32}{2}
=16
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-272)+240}{2*1}=\frac{512}{2}
=256
$